Edit

Route

The Route type is part of the TypeScript specific API for Type Route. It is a helper type useful for getting the type of a particular route. Here's an example:

import { createRouter, defineRoute, Route, param } from "type-route";

const user = defineRoute(
  {
    userId: param.path.string
  },
  p => `/user/${p.userId}`
);

const { routes } = createRouter({
  home: defineRoute("/"),
  user,
  userSettings: user.extend("/settings"),
  userActivity: user.extend("/activity")
});

const groups = {
  user: createGroup([
    routes.user,
    routes.userSettings,
    routes.userActivity
  ])
}

Given the above code the type Route<typeof routes> would evaluate to this type:

  { name: "home", params: {}, ... }
| { name: "user", params: { userId: string }, ... }
| { name: "userSettings", params: { userId: string }, ... }
| { name: "userActivity", params: { userId: string }, ... }
| { name: false, params: {}, ... }

And Route<typeof routes.user> would provide this type:

{ name: "user", params: { userId: string }, ... }

And finally Route<typeof userGroup> would result in this type:

  { name: "user", params: { userId: string }, ... }
| { name: "userSettings", params: { userId: string }, ... }
| { name: "userActivity", params: { userId: string }, ... }

The Route type can be useful in circumstances such as declaring the Props of a component.

import { Route } from "type-route";
import { routes } from "./router";

type Props = {
  route: Route<typeof routes.userSettings>;
};

export function UserSettingsPage(props: Props) {
  const { route } = props;

  return <div>Settings for user {route.params.userId}</div>;
}
← QueryStringSerializerRouterOpts →